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C语言趣味程序百例精解之java实现(56)区分旅客国籍
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程序:
- public class Test56{
- public static void main(String args[]){
- new Test56().whereAreYouFrom56();
- }
-
- /**
- * 56。区分旅客国籍
- *
- * 1美国,2德国,3英国,4法国,5俄罗斯,6意大利
- */
- public void whereAreYouFrom56() {
- int count = 0;
- for (int a = 1; a <= 6; a++)
- for (int b = 1; b <= 6; b++)
- for (int c = 1; c <= 6; c++)
- for (int d = 1; d <= 6; d++)
- for (int e = 1; e <= 6; e++)
- for (int f = 1; f <= 6; f++)
- if (a != 1
- && a != 5
- && a != 2
- && e != 1
- && e != 2
- && e != 5
- && c != 2
- && c != 1
- && c != 5
- && b != 2
- && f != 2
- && a != 4
- && c != 6
- && b != 1
- && c != 4
- && notEquls(new int[] { a, b, c, d, e,
- f })) {
- count++;
- System.out.print(" a=" + a);
- System.out.print(" b=" + b);
- System.out.print(" c=" + c);
- System.out.print(" d=" + d);
- System.out.print(" e=" + e);
- System.out.println(" f=" + f);
- }
- System.out.println("Count =" + count);
- }
- /**
- * 判断是否两两不相等
- */
- public boolean notEquls(int[] a) {
- if (a == null || a.length == 0 || a.length == 1)
- return true;
- for (int i = 0; i < a.length; i++) {
- for (int j = 0; j < a.length; j++) {
- if (a[i] == a[j] && i != j) {
- // System.out.println("a[" + i + "]" + a[i] + " a[" + j +
- // "]"
- // + a[j] + "---");
- return false;
- }
- }
- }
- return true;
- }
- }
- C:at>java Test56
- a=6 b=5 c=3 d=2 e=4 f=1
- Count =1
复制代码 a是意大利人,B是俄罗斯人,c是英国人,D是德国人,E是法国人,F是美国人。
源码下载:http://file.javaxxz.com/2014/11/20/000449859.zip |
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